Bent Pipe Accord






Bent Pipe Accord
a question about fluid mechanics?

Take a beaker filled with water.pressure at its surface will be equal to atmos. pressure.now insert in it a bent pipe which connects it to another beaker L meter above the first one and having its surface parralel to the first one. it will too have pressure equal to atmos. pressure.but according to formula P = Heg the pressure at upper beaker should be (atmos.P)- (Leg )
where is the mistake.

If the tube is filled with water, when the tube is inserted water will flow from the upper beaker to the lower one by siphoning.

The pressure difference will be due to the weight of the water in the upper beaker that is above the surface of the lower beaker.



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