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Please help me on this chemistry problem about finding the volume of gas, i can't solve it!!!
When heated to high temperatures, silver oxide (Ag2O) decomposes to form solid silver and oxygen gas. Calculate the volume of oxygen produced by the decomposition of 6.50 g of Ag2O. The temperature is 22.0 °C and the pressure is 756 mm Hg.
First you have to write out a balanced equation.
Ag2O= 2Ag + O2
Then convert 6.50 g of Ag2O to moles. Divide 6.50 by 231.74. This gives you .0280 moles.
Now you need to find moles of Oxygen. Since Ag2O and O2 have the same coefficient, it is the same number of moles: .0280.
For this you are using the equation. PV=nRT
Pressure needs to be in atm. 756 mm Hg=.994 atm.
You are looking for volume.
n is moles of O2
R is standard at .0821
T is temperature 22 C, but you need to change it to Kelvin so add 273 to get 259.
So now... (.994 atm)(V)=(.0280mol)(.0821)(259K)
V= 1.446 Liters
Read this over and then try it by yourself so you can learn it.
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